Question

What is the value of ‘a’ in this linear equation

Answer 1

Answer:

$\frac{3a + 1}{4} = \frac{a \times 3}{2 \times 3} + \frac{1 \times 2}{3 \times 2}$

$= > \frac{3a + 2}{6}$

$\frac{3a + 1}{4} = \frac{3a + 2}{6}$

$(3a + 1) \times 6 = (3a + 2) \times 4$

$18a + 6 = 12a + 8$

$18a - 12a = 2 \\ 6a = 2 \\ a = \frac{2}{6} = \frac{1}{ 3}$

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