What is the value of a magnetic field in air at a point that is 5 cm from a long straight wire carrying a current of 15A?
Answers
Answer:
refer to the attachment above
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Answer:
What is the magnitude of the magnetic field 1.5 cm from a long, straight conductor carrying a current of 3.2 A?
Answer: .2
¯
6
×
10
−
5
Tesla
Explanation:
It is given that the current carrying wire is long and straight. We assume that it is of infinite length.
The magnitude of magnetic field
∣
∣
∣
→
B
∣
∣
∣
of an infinitely long straight wire can be obtained from the expression
∣
∣
∣
→
B
∣
∣
∣
=
μ
0
I
2
π
r
where
μ
0
=
4
π
×
10
−
7
TmA
−
1
is permeability of free space,
I
is current flowing in the conducting wire and
r
is the radial distance of point of interest.
The direction of the magnetic field which is perpendicular to the direction of current is given by right hand thumb rule as shown in the figure below. Observe that the thumb points in the direction of current and direction in which the fingers curl gives the direction of the magnetic field.
Inserting given values in the expression in SI units we get
∣
∣
∣
→
B
∣
∣
∣
=
4
π
×
10
−
7
×
3.2
2
π
1.5
100
⇒
∣
∣
∣
→
B
∣
∣
∣
=
4.2
¯
6
×
10
−
5
T