Physics, asked by aman7549, 1 year ago

What is the value of acceleration due to gravity in a CGS system?

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Answers

Answered by snehabharti2507
67

Acceleration due to gravity is a vector quantity. Its value of acceleration due to gravity is taken as 9.8 m/s² or 980 cm/s². The S.I. Unit of 'g' is m/s² or 980 cm/s². The S.I. unit of 'g' is m/s² or N/Kg and in C.G.S. system, it is given as cm/s² or dyne/g .


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Answered by Shazia055
0

The value of acceleration due to gravity in the CGS system is $980\,{{cm} \mathord{\left/ {\vphantom {{cm} {{s^2}}}} \right. \kern-\nulldelimiterspace} {{s^2}}}$.

Explanation:

  • The acceleration due to gravity is the acceleration of an object falling towards the earth caused by the gravitational force on the object due to the earth.
  • In SI units, its value is $9.8\,{m \mathord{\left/ {\vphantom {m {{s^2}}}} \right. \kern-\nulldelimiterspace} {{s^2}}}$.  
  • It can be converted into CGS units as shown below.

        $\begin{gathered}  g = 9.8\,\frac{m}{{{s^2}}} \hfill \\  g = 9.8 \times \frac{{100\,cm}}{{{s^2}}} \hfill \\  g = 980{{\,cm} \mathord{\left/ {\vphantom {{\,cm} {{s^2}}}} \right. \kern-\nulldelimiterspace} {{s^2}}} \hfill \\ \end{gathered} $

  • Hence, in the CGS system, the acceleration due to gravity is $980\,{{cm} \mathord{\left/ {\vphantom {{cm} {{s^2}}}} \right. \kern-\nulldelimiterspace} {{s^2}}}$.  

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