Question

what is the value of b°? and what is the process to solve it?​

Answer 1

Answer:

b = 122

Step-by-step explanation:

in dfe c

82+40+a=180

a=58

angle bdf = anglefde (vertically opposite angle)

angle bdf = 82

in dba

angle sum property

B=58

dbc+dba=180 (linear pair)

b+B=180

b=180-58

b=122

Answer 2

Answer:

127°

Step-by-step explanation:

<EDF=<ADB(VERTICALLY OPPOSITE ANGLE)

SO <ADB=82°

IN TRIANGLE ADB sum of interior angle is 180°

so <ABD=180-45+82

=180-127

=53°

now ABC is a straight line so <ABD+<CBD=180°

SO <CBD=180-53=127°