Question

what is the value of (cos2 67°-sin2 23°)

Answer 1

Hey there!

We know that,
cos²B - sin²A = cos(A + B) * cos ( A - B)

Now,
cos²67° - sin²23°
= cos(67 + 23 ) * cos( 67 - 23 )
= cos ( 90 ) * cos45
= 0 * 1/√2 .
= 0



$\therefore$ cos²67 -sin²23 = 0 .

Quick Alternative : [ cos²67-sin²23 = cos²(90-23) - sin²23 = sin²23 - sin²23 = 0 ]

[ cos²67-sin²23 = cos²67-sin²(90-67) = cos²67-cos²67 = 0 ]

Hope helped!

Answer 2

hope this helps you mate enjoy!

im always with the better understanding of the ones who read my answers

plz mark as brainliest