Physics, asked by Harshsahu, 1 year ago

what is the value of d/dx cotx =

Answers

Answered by dainvincible1
16
⇒/dx (cot x) 
d/dx [(cosx)/(sinx)] 
[(cosx)'(sinx)-(cosx)(sinx)']/(sinx)²
[(-sinx)(sinx)-(cosx)(cosx)]/(sinx)²
[(-sin^2(x))-(cos^2(x))]/(sinx)²
-[sin^2(x))+(cos^2(x))]/(sinx)²
-[1]/(sinx)²
∴ the answer is -csc^2 (x)
Answered by Korii
6
It would be equal to 0 since the derivation with the limits corresponds to it's beta value.
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