Question

what is the value of d/dx cotx =

Answer 1

⇒/dx (cot x) 
⇒d/dx [(cosx)/(sinx)] 
⇒[(cosx)'(sinx)-(cosx)(sinx)']/(sinx)²
⇒[(-sinx)(sinx)-(cosx)(cosx)]/(sinx)²
⇒[(-sin^2(x))-(cos^2(x))]/(sinx)²
⇒-[sin^2(x))+(cos^2(x))]/(sinx)²
⇒-[1]/(sinx)²
∴ the answer is -csc^2 (x)

Answer 2

It would be equal to 0 since the derivation with the limits corresponds to it's beta value.