What is the value
of d/dx (sin x tan x)?
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Answer:
sin x(sec x + 1)
Step-by-step explanation:
Use the chain rule:
d/dx(u*v) = u*dv/dx + v*du/dx
Let u = sin x ……. du/dx = cos x
Let v = tan x ……. dv/dx = sec2 x
d/dx(sin x tan x) = sin x * sec^2x + tan x * cos x
= sin x * 1/ cos2x + sin x/cos x * cos x = sin x/ cos2x + sin x = sin x(sec x + 1)
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