Question

What is the value of D for 3x +4y=7 and 2x+3y=5? *

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Answer 1

Given, 3x+4y=7 ->1 and 2x+3y=5->2

1-2=> x+y=2

x=2-y

substitute x in 1

3(2-y)+4y=7

6-3y+4y=7

6+y=7

y=1

substitute y in 1

3x+4(1)=7

3x=3

x=1

So, x=1,y=1

Answer 2

Answer:

Step-by-step explanation:

Let 3x +4y=7 be 1

And 2x+3y=5 be 2

Now, 1-2

= x+y=2

x=2-y

Substitute x in 1,we get

3(2-y)+4y=7

6-3y+4y=7

6+y=7

y=1

Now, Substitute y in 1,we get

3x+4(1)=7

3x=3

$x=\frac{3}{3}$

x=1

Therefore,

x=1

y=1