Math, asked by Raghava7966, 5 months ago

What is the value of discriminant for a quadratic equation 2x²-3x-4=0

Answers

Answered by brijesh992
3

Answer:

D = 41

Step-by-step explanation:

D = b² - 4ac

in given quadratic equation

a= 2, b= -3, c= -4

so, D= (-3)²- 4(2)(-4)

= 9 + 32

= 41

Answered by bg1234
0

Answer:

Discriminant = 41

Step-by-step explanation:

Discriminant (D) = b² - 4ac

a = 2, b = -3, c = -4

D = (-3)² - 4 x 2 x (-4)

D = 9 + 32

D = 41

Quadratic Equation: An equation whose variable's highest exponent is 2.

The general form of a quadratic equation:

ax² + bx + c = 0

where a, b & c are real numbers and a ≠ 0.

Discriminant of a quadratic equation is given as

D = b² - 4ac

  • If D > 0, then two distinct roots
  • If D = 0, then two equal roots
  • If D < 0, then imaginary roots.
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