What is the value of discriminant for a quadratic equation 2x²-3x-4=0
Answers
Answered by
3
Answer:
D = 41
Step-by-step explanation:
D = b² - 4ac
in given quadratic equation
a= 2, b= -3, c= -4
so, D= (-3)²- 4(2)(-4)
= 9 + 32
= 41
Answered by
0
Answer:
Discriminant = 41
Step-by-step explanation:
Discriminant (D) = b² - 4ac
a = 2, b = -3, c = -4
D = (-3)² - 4 x 2 x (-4)
D = 9 + 32
D = 41
Quadratic Equation: An equation whose variable's highest exponent is 2.
The general form of a quadratic equation:
ax² + bx + c = 0
where a, b & c are real numbers and a ≠ 0.
Discriminant of a quadratic equation is given as
D = b² - 4ac
- If D > 0, then two distinct roots
- If D = 0, then two equal roots
- If D < 0, then imaginary roots.
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