Question

What is the value of f(4000) for the function below?
def f(x):
d=0
while x ;= 1:
(x,d) = (x/5,d+1)
return(d)

Answer 1

Return value of the function:

Output:

none

Explanation:

In the given method definition there is some error so, the correct method definition to this question can be describes as follows:

Method definition:

def f(x): #defining a method  

   d=0 #defining a variable d and initializes a value that is 0

   while x == 1: #defining loop to calculate value

       (x,d) = (x/5,d+1) #holding value in x and d variable

   return(d) #return value  

val=f(4000) #calling the method

print(val) #print value

Explanation to this question can be defines as follows:

• In the above code, a method a variable "d" is defined, which initializes a value, that is 0.
• In the next step, a while loop is declared, that holds calculated value in x and d variable and return d variable value, and method is called, that accept a  value, that is "4000", are print is the return value.
• In this method loop value is equal to 1, which is wrong that's why it will print "none".  

Learn more:

• Return type: https://brainly.in/question/9967610