Question

What is the value of friction factor, if the diameter of pipe is 50 cm and roughness height is 0.25 cm

Answer 1

Given :

The diameter of the pipe = d = 50 cm

The roughness height = 0.25 cm

To Find :

The value of friction factor

Solution :

h = Δ f × $\dfrac{L}{D}$ × $\dfrac{V^{2} }{2g}$

where:

h = head loss

f = friction factor

L = length of pipe work

d = inner diameter of pipe work  

v = velocity of fluid

g = acceleration due to gravity

So,

Friction factor = Δ f = $\dfrac{D}{l}$

                        = $\dfrac{50cm}{0.25cm}$

                        = 200

Hence, The Friction factor is 200   Answer