Question

What is the value of (i+1)³³+(i-1)³³=

Answer 1

Answer:(1+i)^33

r=sqrt(2)

argument=pi/4 or 45 degrees

(sqrt(2)^33)(cos(33pi/4)+isin(33pi/(4))

(sqrt(2))^33)((sqrt(2)/2+i(sqrt(2))/2)

I had to use a calculator here to get the final answer as

65536+65536i

(i-1)^33

r=sqrt(2)

argument=3pii/4 or 135 degrees

(sqrt(2)^33)(cos(99pi/4)+isin(99pi/4))

(sqrt(2)^33)(-sqrt(2)/2+sqrt(2)/2)

Again, using a calculator

-65536+65536i

Add both equations together to get

131072i

Step-by-step explanation:

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