What is the value of iota times iota
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1
i*i=i^2=-1 since i =√-1
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0
i^0
= (√-1)^0
= (-1)^(1/2 x 0)]
= (-1)^0
=1
= (√-1)^0
= (-1)^(1/2 x 0)]
= (-1)^0
=1
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