Question

What is the value of k for which the equation x^2 -2kx+7k-12 has equal real roots?​

Answer 1

Answer:k=3,4

Step-by-step explanation:

B^2=4ac

4k^2=4(1)(7k-12)

K^2=7k-12

K^2-7k+12=0

K^2-4k-3k+12=0

K(k-4)-3(k-4)=0

(K-4)(k-3)=0

K=3,4

Hope it helps...