what is the value of k.If one root of the quadratic equation kx square root-7x+12=0 is 3
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hope it will be right
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sadanand2003:
no it is not right.
sorry
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As 3 is the root of the given polynomial then on putting the value of 3 in place of 'X'will give us the equation -
Kx^2 -7x +12=0
On putting the value of 'X' as 3
K(3)^2 -7(3) + 12=0
K(9) -21 +12 =0
9K -9=0
9K=9
K=1
Kx^2 -7x +12=0
On putting the value of 'X' as 3
K(3)^2 -7(3) + 12=0
K(9) -21 +12 =0
9K -9=0
9K=9
K=1
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