Question

What is the value of k if roots are equal in equation 2x²-kx+1=0

Answer 1

Step-by-step explanation:

d=0

b^2-4ac=0

k^2-8=0

K^2=8

k=2√2

Answer 2

Step-by-step explanation:

Given equation is, 2x² - kx + 1 = 0

Since its roots are equal, so its discriminant eill be equal to 0

so,

$= > b^{2} - 4ac = 0$

$= > ({ - k})^{2} - 4.(2).(1) = 0$

$= > {k}^{2} - 8 = 0$

=> k = ± 2√2