Question

What is the value of K, if the roots of 2x² - 6x + k = 0 are real and equal ? *​

Answer 1

Answer:

the value of x is not given by you than we cant find the value of k

Step-by-step explanation:

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Answer 2

2x² - 6x + k = 0 comparing with ax²+ bx + c=0

we get,

a = 2 , b = -6 , c = k

Therefore,

b² - 4ac = (-6)² - 4 × 2 × k

= 36 - 8k

The roots are real and equal.

Discriminant ( ∆ ) = 0

36 - 8k = 0

- 8k = -36

k = -36/(-8)

= 9/2

Ans. the value of k is 9/2 if the roots of 2x² - 6x + k = 0 are real and equal.

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