Question

. What is the value of k in polynomial x² + 8x + k, if-1 is a zero of the polynomial?
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Answer 1

Answer:

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Answer 2

Step-by-step explanation:

The value of k is 7.

Step-by-step explanation:

1. Here polynomial is given

$\mathbf{x^{2}+8x+k}x$

2. Polynomial equation will be written as

$\mathbf{x^{2}+8x+k=0}$

3. Here -1 is zero of

$\mathbf{x^{2}+8x+k}</p><p>$

. It means root of equation

$\mathbf{(x^{2}+8x+k=0)}$

4. It means

x = -1 will satisfied the equation 2)

5. From equation 2)

$\mathbf{x^{2}+8x+k=0} (putting \: value \: of \: x = -1)</p><p>$

$\mathbf{(-1)^{2}+8(-1)+k=0}$

$\mathbf{1-8+k=0}$

$\mathbf{-7+k=0}$

So

So k=7.