what is the value of k in the polynomia x²+8x+k , if -1 is a zero of the polynomial?
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Solution:
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Given:
P(x)= x² + 8x + k,
=> x = -1 ,
=> then P(x)=0, (zero of the polynomial),
_____________________________________________________________
To find:
k = ?
_____________________________________________________________
We know that,
=> P(-1) = 0,.
=> P(-1) = (-1)² + 8(-1) + k
=> 0 = 1 -8 + k
=> 0 = -7 + k
=> -k = -7
=> k = 7,.
_____________________________________________________________
Hope it Helps !!
______________________________________________________________
Given:
P(x)= x² + 8x + k,
=> x = -1 ,
=> then P(x)=0, (zero of the polynomial),
_____________________________________________________________
To find:
k = ?
_____________________________________________________________
We know that,
=> P(-1) = 0,.
=> P(-1) = (-1)² + 8(-1) + k
=> 0 = 1 -8 + k
=> 0 = -7 + k
=> -k = -7
=> k = 7,.
_____________________________________________________________
Hope it Helps !!
Mark as Brainliest,.
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