Question

what is the value of k in the polynomial X square + 8 x + K if -
2 is a zero of the polynomial

Answer 1

Heya !!!


Given that : (-2) is one zero of the given polynomial.


P(X) = X² + 8X + K



Putting X = -2 in,


P(X) = X² + 8X + K



P(-2) = (-2)² + 8 × -2 + K

=> 4 - 16 + K = 0

=> K - 12 = 0

=> K = 12

★ HOPE IT WILL HELP YOU ★

Answer 2

P(x) = x² + 8x + k

P(-2)

=> (-2)² + 8(-2) + k = 0

=> 4 - 16 + k = 0

=> -12 + k = 0

=> k = 12