what is the value of k in the polynomial X square + 8 x + K if -
2 is a zero of the polynomial
Answers
Answered by
14
Heya !!!
Given that : (-2) is one zero of the given polynomial.
P(X) = X² + 8X + K
Putting X = -2 in,
P(X) = X² + 8X + K
P(-2) = (-2)² + 8 × -2 + K
=> 4 - 16 + K = 0
=> K - 12 = 0
=> K = 12
★ HOPE IT WILL HELP YOU ★
Given that : (-2) is one zero of the given polynomial.
P(X) = X² + 8X + K
Putting X = -2 in,
P(X) = X² + 8X + K
P(-2) = (-2)² + 8 × -2 + K
=> 4 - 16 + K = 0
=> K - 12 = 0
=> K = 12
★ HOPE IT WILL HELP YOU ★
Answered by
7
P(x) = x² + 8x + k
P(-2)
=> (-2)² + 8(-2) + k = 0
=> 4 - 16 + k = 0
=> -12 + k = 0
=> k = 12
P(-2)
=> (-2)² + 8(-2) + k = 0
=> 4 - 16 + k = 0
=> -12 + k = 0
=> k = 12
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