Question

What is the value of k so that the pair of liner equations kx-y=2 and 6x - 2y =3 has a unique solution?

Answer 1

Answer:

Step-by-step explanation:

kx-y=2

6x-2y= -3

a1/a2≠ b1/b2

k/6 ≠ -1/-2

2k≠ 6

k≠ 3

therefore the value of k is except 3