Question

What is the value of log 2205?
Given that log 5 = a, log 7= b and log 3 = c
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Answer 1

Answer:

A + 2logB + 2logC

Step-by-step explanation:

E = log 2205

E = log (3² × 5 × 7²)

E = log3² + log 5 + log7²

E = 2log3 + log5 + 2log7

E = 2logC + A + 2logB