what is the value of log 2base 32
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To determine the value of log_(2)32
we use the meaning of logarithms:log_(a)b = x rArr a^x = b
Therefore we let log_(2)32 = x
We rewrite as 2^x = 32
Next, we'll rewrite 32 as a power of 2. 32 = 2^5
2^x = 2^5
Therefore x = 5 as we have the same base
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