Question

What is the value of m, if one of the root of equation x²+mx−5=0 is 2.​

Answer 1

Step-by-step explanation:

$x ^{2} + mx - 5 = 0 \: \: \: is \: 2 \\ 2 ^{2} + 2m - 5 = 0 \\ = > 4 + 2m - 5 = 0 \\ = > 2m = 5 - 4 \\ = > 2m = 1 \\ = > m = \frac{1}{2}$

Answer 2

Answer:

m = 1/2

Step-by-step explanation:

Root of the equation means, the x-value of the equations. Since we are given x = 2, we can substitute in 2 for x, in the equation and solve for m;

=> x² + mx - 5 = 0

=> (2)² + m(2) - 5 = 0

=> 4 + 2m - 5 = 0

=> -1 + 2m = 0

=> 2m = 0 + 1

=> 2m = 1

=> m = 1/2

Hope this helps!