Math, asked by vanshikaarora49, 8 months ago

What is the value of p (E) + p
_
(E)?

Answers

Answered by sagnik777
1

Answer:

-P IS THE CORRECT ANSWER

Step-by-step explanation:

P(E)+P=0

=P(E)=-P

Answered by pulakmath007
0

P(E) + P(Ē) = 1

Correct question : What is the value of P(E) + P(Ē)

Given :

P(E) + P(Ē)

To find :

The value of P(E) + P(Ē)

Solution :

Step 1 of 2 :

Define probability of an event

In any random experiment if the total number of elementary ( simple) events in the sample space be n ( a finite number) among which the number of elementary events favourable to an event E , connected with the experiment be m then the probability of the event E is denoted by P (E) and defined as

 \displaystyle \sf{}P(E) =  \frac{m}{n}

Now the total number of possible outcomes = n and the total number of possible outcomes for the event E is m

Step 2 of 2 :

Find the value of P(E) + P(Ē)

Ē is the event of not occurring E

Then total number of possible outcomes for the event Ē is n - m

Thus we get

\displaystyle \sf  P(\bar{E})

\displaystyle \sf =  \frac{n - m}{n}

\displaystyle \sf  = 1 -  \frac{m}{n}

\displaystyle \sf    =  1- P({E})

Hence we get

\displaystyle \sf  P(E) + P(\bar{E})

\displaystyle \sf = P(E) + 1 - P(E)

= 1

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