What is the value of p if -3 is one of the zeroes of the polynomial 5y² - py -18
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Answer:
p = -9
Step-by-step explanation:
Let p(y) = 5y² - py -18
Put y= -3 in the given equation
p(-3) = 5(-3)² - p(-3) -18
0= 5×9 +3p-18
0= 45-18 +3p
0= 27+3p
-27= 3p
-27÷3= p
-9= p
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