Question

= (x^2-4) × (x^2-5)​

Answer 1

$(x ^ { 2 } -4) \times (x ^ { 2 } -5) \\ = x^{4}-9x^{2}+20$

Answer 2

Answer:

${\huge{\fcolorbox{aqua}{navy}{\fcolorbox{yellow}{teal}{\bf{\color{yellow}{⫷AnSwEr⫸➺}}}}}}$

$\tt( {x}^{2} - 4 ) \times ( {x}^{2} - 5)$

$\tt {x}^{ {2}^{2} } + {x}^{2}( (- 4 )+ (- 5) )+ - 4 \times - 5$

$\tt {x}^{4} + - {9x }^{2}+ 20$

$\huge \tt{ \blue{identit \: used}}$

$\tt \: x + a \times x + b = {x}^{2} + x \times (a + b )\times ab$