Question

what is the value of p if X + 1 upon 2 is a factor of p x square - 4px + 3

Answer 1

$\textbf{\huge{\underline{ Hello Mate! }}}$

Here, value of x = - 1 / 2

$f(x) = p {x}^{2} - 4px + 3 \\ f( \frac{1}{2} ) = p( { \frac{1}{2}) }^{2} - 4p \times \frac{1}{2} + 3$

Since x + 1 / 2 is factor so $\textsf{\red{ final value of x will be "0" }}$

$0 = \frac{1}{4} p - 2p + 3 \\ 0 = \frac{1p - 8p}{4} + 3 \\ 0 = \frac{7p}{4} + 3 \\ - 3 = \frac{7p}{4} \\ - 3 \times \frac{4}{7} = p \: and \: p = - \frac{12}{7}$

$\textbf{ Have great future ahead! }$