what is the value of p if x-2 is a factorofx2-6x+p?
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Answered by
1
Answer:
p(x) = x² - 6x + p = 0
As, x-2 is a factor of p(x)
therefore,p(2) = 2²-6(2)+p = 0
=> 4 - 12 + p = 0
=> -8 + p = 0
=> p = 8
Answered by
0
Answer:
8
is the
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