Question

what is the value of p when px^3 + 16x^2 + 8x - 32 is divided by (x + 2) , leaving 0 as remainder ?

Answer 1

p(x)=px^3+16x^2+8x-32
x+2=0
x=-2
p(-2)=p(-2)^3+16*-2^2+8*-2-32
=-p8+16
-p8=-16
p8=16
p=16/8
p=2
So if you will put value of p as 2 you will get remainder 0 .

Answer 2

Answer:

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