Question

What is the value of (root11-root7)(root11+root7)

Answer 1

Answer:

(√11-√7)(√11+√7)

(√11)²-(√7)²                            [ (a+b)(a-b)=a²-b² ]

11-7=4

Step-by-step explanation:

Answer 2

Answer:

4

Step-by-step explanation:

you just apply an identity

a^2-b^2=(a+b)(a-b)

(√11)^2-(√7)^2

11-7

4

pls mark me as brainliest