Question

What is the value of sin^2 62°+cos^2 62° ?​

Answer 1

Answer:

1

Step-by-step explanation:

sin2 62° + cos2 62°

since [sin2 A + cos2 A =1]

therfore sin262° +cos262° =1

Answer 2

The value of $sin^2 62° + cos^2 62°$ is 1.

The value of$sin^2 62° + cos^2 62°$ is equal to 1.

This is a well-known trigonometric identity, known as the Pythagorean identity, which states that for any angle x,

$sin^2(x) + cos^2(x) = 1$

Substituting x = 62°, we get:

$sin^2 62° + cos^2 62° = 1$

Using the identity of trigonometric functions, we know that:

$sin² θ + cos² θ = 1$

Therefore, in this case, we have:

$sin² 62° + cos² 62° = 1$

So the value of$sin² 62°+cos² 62°$ is 1.

Therefore, the value of $sin^2 62° + cos^2$62° is 1.

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