Question

what is the value of sin18° cos 36°​

Answer 1

Answer:

(sin 18^{\circ})(cos 36^{\circ})=0.25

Step-by-step explanation:

Given : (sin 18^{\circ})(cos 36^{\circ}) ........(1)

Evaluate:

sin(18^{\circ})= 0.309

cos(36^{\circ})= 0.809

Putting value in equation (1) we get,

(sin 18^{\circ})(cos 36^{\circ})

=(0.309)(0.809)

=0.309\times0.809

=0.249

=0.25

Therefore,(sin 18^{\circ})(cos 36^{\circ})=0.25

Answer 2

Answer:

first you have to convert sin into cos by doing sin=cos(90-t).

cos(90-18) cos36

cos36 cos36

1×1

The answer will be 1

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