What is the value of SinA+SinB?
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Answer:
SinA+ sinB =2[{sin(A+B)/2}{ cos(A-B) /2}]
proof:
sin(X+Y) + sin(X-Y) = 2(sinXcosY)
let X + Y = A
and X - Y = B
=> X = (A + B)/2 & Y = (A - B)/2
By Substituting, we obtain the following equation
sinA+ sinB =2[{sin(A+B)/2}{ cos(A-B) /2}]
Step-by-step explanation:
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