what is the value of sin@with respect to cot@. here @is teetha
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In trigonometrical ratios of angles (180° + θ) we will find the relation between all six trigonometrical ratios.
We know that,
sin (90° + θ) = cos θ
cos (90° + θ) = - sin θ
tan (90° + θ) = - cot θ
csc (90° + θ) = sec θ
sec ( 90° + θ) = - csc θ
cot ( 90° + θ) = - tan θ
☠️☠️
In trigonometrical ratios of angles (180° + θ) we will find the relation between all six trigonometrical ratios.
We know that,
sin (90° + θ) = cos θ
cos (90° + θ) = - sin θ
tan (90° + θ) = - cot θ
csc (90° + θ) = sec θ
sec ( 90° + θ) = - csc θ
cot ( 90° + θ) = - tan θ
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Here, sin theta and cos theta are complementary angles that is they both add up to 90 degree
Cos = sin (90- theta) and vice versa
Thank you!!
Cos = sin (90- theta) and vice versa
Thank you!!
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