Question

What is the value of t if 2t³-5t²+t+2=0

Answer 1

Step-by-step explanation:

2t^3-5t^2+t+2=0

Take t^2 as common from 2t^3-5t^2

then t^2(2t-5)+t+2=0

= 2t-5+t+2=0/t^2

= 3t-3=0

= 3t=0+3

3t=3

t=3/3

t=1