What is the value of tan 20° + tan 40° + √3 tan20° tan40°?
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Answered by
41
we know, tan(A + B) = (tanA + tanB)/(1 - tanA.tanB)
tan60° = tan(20° + 40°)
or, √3 = (tan20° + tan40°)/(1 - tan20°. tan40°)
or, √3(1 - tan20° . tan40°) = tan20° + tan40°
or, √3 - √3 . tan20° . tan40° = tan20° + tan40°
or, √3 = tan20° + tan40° + √3tan20°. tan40°
hence, tan20° + tan40° + √3tan20°. tan40° = √3
tan60° = tan(20° + 40°)
or, √3 = (tan20° + tan40°)/(1 - tan20°. tan40°)
or, √3(1 - tan20° . tan40°) = tan20° + tan40°
or, √3 - √3 . tan20° . tan40° = tan20° + tan40°
or, √3 = tan20° + tan40° + √3tan20°. tan40°
hence, tan20° + tan40° + √3tan20°. tan40° = √3
Answered by
30
HELLO DEAR,
we know:-
tan(A + B) = (tanA + tanB)/(1 - tanA.tanB)
now,
tan60° = tan(20° + 40°)
=> √3 = (tan20° + tan40°)/(1 - tan20°. tan40°)
=> √3(1 - tan20° . tan40°) = tan20° + tan40°
=> √3 - √3 . tan20° . tan40° = tan20° + tan40°
=> √3 = tan20° + tan40° + √3tan20°. tan40°
hence,
tan20° + tan40° + √3tan20°. tan40° = √3
I HOPE IT'S HELP YOU DEAR,
THANKS
we know:-
tan(A + B) = (tanA + tanB)/(1 - tanA.tanB)
now,
tan60° = tan(20° + 40°)
=> √3 = (tan20° + tan40°)/(1 - tan20°. tan40°)
=> √3(1 - tan20° . tan40°) = tan20° + tan40°
=> √3 - √3 . tan20° . tan40° = tan20° + tan40°
=> √3 = tan20° + tan40° + √3tan20°. tan40°
hence,
tan20° + tan40° + √3tan20°. tan40° = √3
I HOPE IT'S HELP YOU DEAR,
THANKS
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