What is the value of tan theta = |2+√3| ? Please tell me how to solve in detail .
Please solve it's urgent .
Answers
Answered by
1
use the formula tan(a+b) = (tan a + tan b)/(1-(tan a× tan b)
pkdivyesh:
are u frm 12th if yes I have a chem dought
no im in diploma 1st year engineering
kk
thks
and guys sorry for the wrong answer
It's ok .
its ok
n sry too for rude behavior
np
thnx
Answered by
1
use (tan A + tan B)formula
(tanA+tanB)= (tanA+tanB÷1-tanA×tanB)
Now substitute those values
therefore tan √3=60
tan theta= |2+√3|
=2+60
tan-60=2
tan60= -2
(tanA+tanB)= (tanA+tanB÷1-tanA×tanB)
Now substitute those values
therefore tan √3=60
tan theta= |2+√3|
=2+60
tan-60=2
tan60= -2
There is also theta
you missed theta in the last two lines .
oh sry
actually 60 is the value of theta
you mean the final value of theta 60 ?
but the final value of theta is 5π/12
multiply 5 by π where π value is 180 and then divide it by 12
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