Question

what is the value of
${i}^{ - 9}$
​

Answer 1

Answer:

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"i" lies one unit above zero. Multiplying it by "i" rotates it leftward and downward onto the real-number line to the point at -1.

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

i = √-1

i^2=-1

i^3=i. i^2=-i

i^4=1

i^8=1

i^9=i.i^8

=i

now acc. to question i^-9=1/i^9

=1/i

multiple or divide by i

we get

i/i^2

=-i ans.

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