what is the value of
flw me on Ig akshatdubey912
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Step-by-step explanation:
Let sin70⋅sin50−cos85⋅cos65=I
Using 2sinAsinB=cos(A+B)−cos(A−B)
2cosAcosB=cos(A−B)+cos(A+B)
We get,
I=21(cos20−cos120−cos150−cos20)
=21(−cos120−cos150)
=21(sin30+sin60)
=21(21+23)
=43+1
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