Question

What is the value of the shunt resistance that allows 20% of the main current through a galvanometer of 99 Ω ?​

Answer 1

Answer:

NEED AND significance of pollination::-

↔️↔️ pollination leads to fertilization and production of seeds and fruits

↔️it prevents ovary abscission

Answer 2

Answer:

The value of the shunt resistance is 24.75Ω.

Explanation:

The current through the galvanometer is given by;

$I=I_g(1+\frac{G}{s})$         (1)

Where,

I=total current

Ig=current through the galvanometer

G=resistance of the galvanometer

G=resistance of the galvanometer

s=shunt resistance

From the question we have,

I=I

Ig=20% of the main current=0.2I

G=99Ω

By substituting the value of I, Ig, and G in equation (1) we get;

$I=0.2I(1+\frac{99}{s})$

$\frac{10}{2}=1+\frac{99}{s}$

$\frac{99}{s}=5-1=4$

$s=\frac{99}{4}=24.75\Omega$

Hence, the value of the shunt resistance is 24.75Ω.