What is the value of triple product A.(B×A) when the angle between A and B is theta?
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Explanation:
We know that the resultant vector of the cross product of two vectors is perpendicular to both of them (which is obtained by the hand rule).
Let B×A=C
Then: A.C= AC cos 90°(since C is perpendicular to A as well as B)
Now, cos90°=0
Hence,A.C=AC×0=0
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