Question

What is the value of x for which (x+2), 2x, (2x+3) are three consecutive terms of an AP?​

Answer 1

Answer:

Given,

x+2,2x,2x+3 are in A.P.

⇒(2x)−(x+2)=(2x+3)−(2x)

2x−x−2=2x+3−2x

x−2=3

∴x=5

The consecutive numbers are : 5+2,2(5),2(5)+3

⇒7,10,13

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