Question

what is the value of x in the below figure ​

Answer 1

Answer:

x=60°

Step-by-step explanation:

p+q+r=180°(sum of interior angle=180°)

90°+30°+x=180°

120°+x=180°

x=180°-120°

x=60°

Answer 2

$\huge\sf{\bold\purple{Question -} }$

What is the value of "x" in the above figure ? (*refer to the attachment)

$\huge\sf{\bold\pink{Answer -} }$

As we know,

$\fbox\orange{angle sum of a ∆ = 180°}$

✳ Here, in ∆PQR,

⠀⠀∠RQP = 30°

⠀⠀∠QPR = 90°

⠀⠀∠PRQ = x°

The angle sum of ∆PQR would also be 180°.

So, we got an equation, i.e –

$∠P + ∠Q + ∠R = 180° \\ \Rightarrow 90°+30°+x° = 180° \\ \Rightarrow 120° + x° = 180° \\ \Rightarrow x = 180-120 \\ \\ \Rightarrow \fbox{x = 60°}$

∴ value of x is 60°

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✍️Some more to know :

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Angle sum of any polygon =

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀(n-2)×180°

where, "n" is the no. of sides.

→ Let's take an example of "Hexagon" i.e a six-sided polygon and find it's angle sum.

No. of sides = 6

Angle sum = (6-2)×180°

Angle sum = 4×180°

Angle sum of a hexagon = 720°