what is the value of x1 ?.....(Image attached)
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I am denoting 'lambda' by ¥.
4 - 3(x1)^2 - ¥ = 0........equation 1.
Now, from second equation,
2 - ¥ = 0
¥ = 2...●
Now, we put the value of ¥ in equation 1.........
4 - 3(x1)^2 - 2 = 0
2 - 3(x1)^2 = 0
3(x1)^2 = 2
(x1)^2 = 2/3
x1 = √(2/3)....●
Thus value of x1 = √(2/3)..●
●●●●●●●●●●●●●●●●●●●●
Hope it was helpful.
4 - 3(x1)^2 - ¥ = 0........equation 1.
Now, from second equation,
2 - ¥ = 0
¥ = 2...●
Now, we put the value of ¥ in equation 1.........
4 - 3(x1)^2 - 2 = 0
2 - 3(x1)^2 = 0
3(x1)^2 = 2
(x1)^2 = 2/3
x1 = √(2/3)....●
Thus value of x1 = √(2/3)..●
●●●●●●●●●●●●●●●●●●●●
Hope it was helpful.
Aiswarya14:
Buddy....in the equation it is X1^2 ( x1 square) is given. so what is the value of x1 ?
Ohh..sorry...I didn't see..buut now I have corrected that.
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