what is the value of xy
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(x+y)^3=x^3+y^3+3xy(x+y)______(1)
(x+y)(x^2+y^2+2xy-3xy)=x^3+y^3
(x+y)(x^2+y^2-xy)=x^3+y^3
x+y=b/a
now from ___1
(b/a)^3=b+3xyb/a
(b^3- a^3b)/3*a^3=b*xy/a
xy=(b^2-a^3)/3*a^2
(x+y)(x^2+y^2+2xy-3xy)=x^3+y^3
(x+y)(x^2+y^2-xy)=x^3+y^3
x+y=b/a
now from ___1
(b/a)^3=b+3xyb/a
(b^3- a^3b)/3*a^3=b*xy/a
xy=(b^2-a^3)/3*a^2
theking12310:
sorry bro your answer is not there in option
now the answere is correct
how you got (b^3-a^3 b)/3a^3= b*xy/a
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Hope it helps you mate and Mark me as brainlest
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