Math, asked by theking12310, 1 year ago

what is the value of xy​

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Answers

Answered by Anonymous
1
(x+y)^3=x^3+y^3+3xy(x+y)______(1)

(x+y)(x^2+y^2+2xy-3xy)=x^3+y^3

(x+y)(x^2+y^2-xy)=x^3+y^3

x+y=b/a

now from ___1

(b/a)^3=b+3xyb/a

(b^3- a^3b)/3*a^3=b*xy/a

xy=(b^2-a^3)/3*a^2

theking12310: sorry bro your answer is not there in option
theking12310: now the answere is correct
theking12310: how you got (b^3-a^3 b)/3a^3= b*xy/a
Answered by mayurs413
0

Step-by-step explanation:

Hope it helps you mate and Mark me as brainlest

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