Question

What is the value of y in the equation 2(3y + 6 + 3) = 196 − 16? 27 29 30 33

Answer 1

Hey

2(3y+6+3)=196

distribute 2*3y, 2 and 6, and 2 and 3 which gives you 6y+12+6=196

then subtract 6 from 196 which leaves you with 190

then add the two sums 6y and 12 and divide this total by 190

That's your answer

Answer 2

2(3y + 6 + 3) = 196 − 16
or 6y + 12 + 6 = 180
or 6y = 180 - 18
or y = 162/6
or y = 27

Hope it'll help you dear ^_^