Question

What is the value stored in x after evaluating the expression? x=10; x *= x++ + ++x *5 - x--;

Answer 1

Answer:

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Explanation:

x++ =5 so..

5*2 = 10

(x=6 here the increment happends after the value is used)

3*5 ➡(1 is taken from x first before the value is used this is why its 5 again)

5*2 = 10

3*5 = 15

x = 25