what is the value ?
with solution please
Attachments:
Answers
Answered by
0
z=2-3
therefore
=4(2-3)^3-3(2-3)^2+169
=4(-1)^3-3(-1)^2+169
=4(-1)-3(1)+169
=-4-3+169
=162
therefore
=4(2-3)^3-3(2-3)^2+169
=4(-1)^3-3(-1)^2+169
=4(-1)-3(1)+169
=-4-3+169
=162
arshwa:
options are 0 , 160 , 140 , 199
Similar questions