Question

What is the volume (in ml) of 0.1 M potassium permanganate solution required to completely oxidise
100 ml of 0.5 M ferrous sulphate solution in acidic medium?
a) 20
b) 200 c ) 50 n
d) 100
​

Answer 1

Answer:20ml

Explanation:

M1V1=M2V2

0.1×100=0.5×V2

V2=20

Answer 2

The volume of potassium permanganate solution required is 100 mL

Explanation:

The chemical equation for the oxidation of ferrous sulphate solution by potassium permanganate in acidic medium follows:

$2KMnO_4+8H_2SO_4+10FeSO_4\rightarrow K_2SO_4+5Fe_2(SO_4)_3+2MnSO_4+8H_2O$

To calculate the volume of potassium permanganate solution, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of potassium permanganate solution

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of ferrous sulphate solution

We are given:

$n_1=10\\M_1=0.1M\\V_1=?mL\\n_2=2\\M_2=0.5M\\V_2=100mL$

Putting values in above equation, we get:

$10\times 0.1\times V_1=2\times 0.5\times 100\\\\V_1=\frac{2\times 0.5\times 100}{10\times 0.1}=100mL$

Learn more about neutralization equation:

https://brainly.com/question/8964836

https://brainly.com/question/14798345

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